DAILY COUGAR PUZZLE
DEPARTMENT OF MATHEMATICS
The puzzle appears in the
University of Houston Daily Cougar
for two days, twice a month, during September, October and November during the
fall semester and February, March and April during the spring semester.
RULES FOR THE PUZZLE CONTEST
( 1.) Anyone may submit a solution to a puzzle.
( 2.) A solution may only be submitted either by
(a.) email
to puzzle@math.uh.edu
or
(b.) in person, at the reception desk of the Department of Mathematics
in a properly marked envelope.
( 3.) In order to be eligible for the contest, a
submission must be received no later
than five (5) days after the first
appearance of the puzzle in the Daily Cougar.
( 4.) All solutions submitted must have the full name of the submitter and an
email address to contact the submitter.
( 5.) All timely submitted solutions will be graded by
the Mathematics Department.
( 6.) The University of Houston undergraduate student submitting the best correct solution will be awarded a $50 gift certificate by
the Mathematics Department.
( 7.) The winner of the gift certificate will posted in
the Daily Cougar and will also be notified by email.
( 8.) All puzzle decisions as to best and correctness
are made by the Mathematics Department and the decisions are final.
( 9.) A winner, if any, and a solution for each of the
puzzles will be posted at this Mathematics Department Cougar Puzzle web site.
(10.) A record is kept of the
solvers for each month and the top undergraduate problem solver for the entire academic
year will receive a $250 gift certificate from the Mathematics Department and is qualified to attend the US National
Collegiate Mathematics Championship. The 2007 USNCMC was held in San Jose, California
this past August.
Some
of the puzzles are supplied by: ÒThe Problem Solving CompetitionÓ.
DAILY
COUGAR SOLUTIONS
DC PUZZLE NUMBER 1
Winner: Ms. Melody Lam
PRIME
NUMBERS
Determine if there is a
positive integer n such that both 2n + 1 and 2n – 1
are prime numbers. If there is such a number, then determine all such.
Carefully justify your answer.
SOLUTION
Note that 2n is
not divisible by 3 and if x, y and z are three consecutive positive integers,
one of x, y or z is divisible by 3. Thus either 2n + 1 or 2n
– 1 must be divisible by 3. Further, if both of these numbers are to be a
prime number, then one of them must be 3.
If 2n – 1 is 3, then 2n + 1 is 5 (n
= 2).
If 2n + 1 is 3, then 2n – 1 is 1 (n
= 1).
But the number 1 is not a
prime number.
Therefore 2 is the only
possible choice for the integer n.