LINEAR ALGEBRA and
DIFFERENTIAL EQUATIONS
Using MATLAB

Martin Golubitsky and Michael Dellnitz

Corrections

Page Line Correction
2   In paragraph 2 interchange $m$ with $n$ and $m'$ with $n'$
3   Interchange problems 2 and 3
62 7 and the $m$ vector
62 8 $b = \left(\begin{array}{c} b_1  \vdots  b_m \end{array}\right)$
63 -3 vector using matrix product in Matlab.
66 (3.1.7) Entry of $A$ in row 4, column 5 should be 8.0
75 -6 ...what functions $L:{\bf R}\to{\bf R}$ are linear.
75 -5 Since we are looking at the special case of linear mappings on ${\bf R}$, we note that $x$ is a
    real number as well as a vector. Thus
75 -3,-2 In addition, if $L:{\bf R}\to{\bf R}$ is linear, we can use Definition 3.3.1(b) ...
103 5 $L_A(P)=\{Az: z\in P\}$
103 -9 $\vert L_A(P)\vert = \cdots$
103 -5 $P = L_B(S)$.
103 -4 $\vert L_A(P)\vert = \vert L_{AB}(S)\vert$
105 3 $L_A(S)$
138 -5 $g(x) \neq 0$
146 16 Sinks: $a < 0$ and $d<0$
152 4 $(x(t),y(t))=(\cos t, -\sin t)$ is a solution
174 8 $-3.0253 e^{2.3543t}\left(\begin{array}{r} -0.9830  -0.1838 \end{array}\right) + \cdots$
188 -4 $0v = \mathbf{0}$
189 -6 Let $W$ be a nonempty subset ...
199   Change $A$ to $W$ in lines 1, 3, 7, 10, 12
200   Change $A$ to $W$ in lines 7, 10, 16, 18
203   Change $A$ to $W$ in lines 5, 8, 10, 11, 15, 16
204   Change $A$ to $W$ in lines 6, 8, 11
207 8 equations
207 11 on the matrix $M$ defined in Lemma 5.5.4.
228 16 eigenvalue of the real $2\times 2$ matrix $C$
237 10 $C^4=I_2$
238 1 To compute the matrix exponential, MATLAB ...
241 -8 $\dot{X}=\left(\begin{array}{cc} \lambda_1 & 1  0 & \lambda_1\end{array}
\right)X$
248 -4 by $v_2$, we calculate
252 10 $e^{tC} = \frac{1}{\lambda_1-\lambda_2} \cdots$
285 -4 $n\ge 3$
289 3, 5, 7 Change $I_n$ to $I_m$
294 -9 induction. The simplest meaningful case ($n=2$; $k=1$) is easily verified.
298 8, 9 Replace ``Note here that'' with ``By definition''
298 11 and therefore, by Theorem 3.7.8, there exists
323 5 ...Lemma 9.1.3,
323 14 Theorem 9.1.2 states ...
333 15 ...$z_2 =(-1,2)$
333 -3 $C_{\mathcal{WZ}} = \left(\begin{array}{rr} 1 & 1 1 &-2\end{array}\right)^{-1}\left(\begin{array}{rr} 1 & -1 3 &2\end{array}\right)$
  -2 $= \frac{1}{3}\left(\begin{array}{rr} 2 & 1 1 &-1\end{array}\right)\left(\begin{array}{rr} 1 & -1 3 &2\end{array}\right)$
  -1 $= \frac{1}{3}\left(\begin{array}{rr} 5 & 0 -2 &-3\end{array}\right)$
350 10 made in using ...
350 -3 b0(1) = -3.8197
350 -1 b0(3) = 0.0443
365 -1 replace $w_i^2$ with $w_j^i$
376 9 using the notion of differentiability in two variable calculus, but ...
387 -4 $x^2+y^2=r_0^2$
401 4 & 7 $\dot{y} = y(-4+x)$
408 -1 ...that the linearization at the origin ...
409 -1 In Figure 12.9 -- no change in weight of dots
412 5 Delete the sentence ``We discuss homoclinic ...Section 12.2.''
413 1 In Figure 12.12 -- no change in weight of dots
414 1 In Figure 12.13 -- branch of limit cycles off top branch should be dotted
423 1 In Figure 12.16 -- branch of limit cycles off top branch should be dot-dashed
427   problem 3. $\rho=-0.04$
428 6 (11.4.5)
429 6 $f(x,\rho) = \frac{1}{2}ax^2 + \rho$
449 6 if there is an invertible complex
454 1 e13_2_13
454 -7 in real block diagonal form
466 -7 $\begin{array}{lrr} {\rm null2 =} & \\
& 0.2690 & 0.1605 \\
& 0.6773 & -0.6937 \\
& -0.6712 & -0.6749 \\
& -0.1357& 0.1935
\end{array}$
467 1 $\begin{array}{lr} {\rm v11 =} & \\
& -0.8093 \\
& 2.8327 \\
& 3.2374 \\
& -0.8093
\end{array}$
467 6 Note that V11 is nonzero and a multiple of the eigenvector. Thus, we ...
482   Equation (14.1.2): $+\frac{1}{(k-1)!}t^{k-1}N^{k-1}$
486 4,-14 - -12 Change $I_n$ to $I_4$
490 -7 $s\times s$ matrix
490 -5 $u\times u$ matrix
490 -3 $c\times c$ matrix
491 12 $z(t)$ can be either bounded or grow.
493 5 e14_2_4
494   In problem 14.2.2 change to $+z^3$ in $\dot{x}$ equation and $-x^3$ in $\dot{z}$ equation
507 11 $[t,x] = \mbox{ode45}('f14\_4\_4', [0 50], [0.5, 0.4, 0.3]');$
539 -2 $\{t^je^{\lambda_\ell t}: \cdots$
541 -6 with algebraic multiplicity
566 7 $x_p(t) = -e^{2t}$
566 10 $x(t) = -e^{2t} + \alpha e^{3t}$
566 11 $\alpha = 2$
599 -1 $c(t) = \int_{t_0}^t g(\tau)e^{-H(\tau)}d\tau + x_0e^{-H(t_0)}$
602 -5 $X_j(0) = v_j$.
620 -1 $\frac{v^2}{2} = 2(\ln(t)-\ln(2)) + \frac{9}{2}$
621 2 $v(t) = \sqrt{9+4\ln\frac{t}{2}}$
621 4 $x(t)=tv(t) = t\sqrt{9+4\ln\frac{t}{2}}$
635 9 Change $V(x)$ to $V'(x)$ in (17.7.5)
635 -3, -2 Change $V(x)$ to $V'(x)$
636 3,6 Change $V(x)$ to $V'(x)$
637 6, 7 Change $V(x)$ to $V'(x)$
675 5 Section 1.1, Problem 3: answer given is to Problem 2. Problem 3 answer is: $(8,4,12)$
681 -4 3. $X(t) =\frac{7}{3}e^t \cdots$
684 6 $
\left(\begin{array}{r} x(t)  y(t) \end{array} \right) = \left(\begin{array}{...
...{2t}(\cos(3t) - 2\sin(3t))  -e^{2t}(\sin(3t) + 2\cos(3t)) \end{array} \right)$
695 -4 7. $\frac{1}{2e^{2-t}-1}$
Corrections to Solutions Manual
8 -2 y = 2 - x.*sin(x.^2 - 1);

The toolbox file e12_2_14.pps is incorrect. The correct file can be downloaded from

ftp.math.uh.edu/pub/laode/matlab6_files/e12_2_14.pps