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Proof : if \(\alpha=p/q\) is a solution of \(P(x)=0\) then \(\beta=p/q-k\) is a solution of \(P(y+k)=0\); compute that \(Q(y):=P(y+k) = a_n y^n + \dots + P(k)\), so the numerator \(p-k q \) of \(\beta=p/q-k\) must divide the constant term of \(Q(y)\), which is \(P(k)\).
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